2x(1-3x)+6(x^2-2)=0

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Solution for 2x(1-3x)+6(x^2-2)=0 equation:


Simplifying
2x(1 + -3x) + 6(x2 + -2) = 0
(1 * 2x + -3x * 2x) + 6(x2 + -2) = 0
(2x + -6x2) + 6(x2 + -2) = 0

Reorder the terms:
2x + -6x2 + 6(-2 + x2) = 0
2x + -6x2 + (-2 * 6 + x2 * 6) = 0
2x + -6x2 + (-12 + 6x2) = 0

Reorder the terms:
-12 + 2x + -6x2 + 6x2 = 0

Combine like terms: -6x2 + 6x2 = 0
-12 + 2x + 0 = 0
-12 + 2x = 0

Solving
-12 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 2x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 2x = 0 + 12
2x = 0 + 12

Combine like terms: 0 + 12 = 12
2x = 12

Divide each side by '2'.
x = 6

Simplifying
x = 6

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